In the diagram shown, the charge + Q is fixed. Another charge +2q, is projected from a distance R from the fixed charge. Minimum separation between the two charges if the velocity becomes 
times of the projected velocity, at this moment is (Assume gravity to be absent)
A
B
C
D
4 R
Text Solution
Verified by ExpertsThe correct answer is:
A
By conservation of angular momentum about +Q charge m V × sin 30 0 R = m × 
× d
d = 
R
Prepare Smarter with CGP Edu
Get practice questions, solutions, and test series in one place.
Write a Review
Share your experience with this question and solution.
Commentary
Send your comment, doubt, correction, or feedback to admin.
Similar Questions
Explore conceptually related problems
Two bodies of masses and have equal kinetic energies. If and are their respective momentum, the…
Work done in raising a box depends on
A light and a heavy body have equal momenta. Which one has greater K.E
A body at rest may have
The kinetic energy possessed by a body of mass m moving with a velocity v is equal to , provided
If the momentum of a body is increased n times, its kinetic energy increases